Document number: | not submitted |
Date: | 2014-03-27 |
Project: | JTC1.22.32 Programming Language C++ |
Reply-to: | Rouslan Korneychuk <rouslank at msn dot com> |
This proposal suggest adding a short-hand notation for creating aliases to base classes within the scope of class.
e.g.:
class A : protected B = C, public D { public: A() : B(3) {} void do_something() { /* ... */ B::do_something(); } };
which would be approximately equivalent to:
class A : protected C, public D { protected: typedef C B; public: A() : B(3) {} void do_something() { /* ... */ B::do_something(); } };
The difference being that in the proposed syntax, the name B
is specified sooner and thus could be used in the second
base-specifier. The name B
would always
have the same accessibility as the name C
.
Most of the time, a class' base class can be easily referred to by its name due to class name injection, but there are a few cases where this does not work and if the base class is a template, requires either repeating template parameters or a work-around.
e.g.:
template<typename T,typename Pasta> class monstrous : public something< monstrous<T,Pasta>, allocator<monstrous<T,Pasta>>, comparison<monstrous<T,Pasta>, and_so_on<Pasta>, and_so_forth<T,etc<T>>> { /* ... */ };
A very long instantiation such as this is particularly undesirable to have to
repeat. The injected name something
cannot be used because the
definition of its class is not available before monstrous
is
defined.
e.g.:
// elsewhere: template<typename Alloc> using particular_t = typename particular<Alloc>::type; /* ... */ class A : public particular_t<my_allocator<double>> { /* ... */ };
Here again the base class cannot be referred to by particular_t
,
since that is not its name. Looking at the definition of
particular_t
it looks like type
is its name, but that
might not be so. type
might actually be a
typedef to another name, and in fact, the actual
name of the class may vary depending on the template parameter.
class A : public B<X>, public B<Y> { /* ... */ };
Here the name B
is ambiguous.
The first example can be solved like so:
template<typename T,typename Pasta> class monstrous : public something</* ... */> { typedef typename monstrous::something base_t; /* ... */ };
This, however, will not solve the problem in the other two examples.
A particular template instantiation may be declared in a typedef before being
used in a derived class. Disadvantages: this pollutes the namespace with extra
names, and doesn't work in the first case. In the first case, one could forward
declare monstrous
and declare a template alias with the same
parameters, but this would only exchange duplicating the base class' arguments
with duplicating the parameters of the derived class.
An extra template parameter can be added to the derived class to be used in place of the base class, with a default value of the base class that is desired. e.g.:
template<typename T,typename B=some_base</*...*/>> class some_class : public B { /* ... */ };
Disadvantages: This solution is not obvious, doesn't work for the first case
(the names B
and some_class
are not available at that
point) and would require turning a plain class into a template if it wasn't one
already.
Work is underway to develop a reflection standard for C++, so in the future,
given a class A
, one will probably be able to refer to—for
example— the first direct base class with something like
std::base_t<A,0>
. This however lacks the informativeness of a
meaningful name and is brittle, since adding, removing or reordering base
classes would change the numbering.
The proposed syntax would allow resolving the issues in the examples like so:
// example 1 template<typename T,typename Pasta> class monstrous : public base_t = something< monstrous<T,Pasta>, allocator<monstrous<T,Pasta>>, comparison<monstrous<T,Pasta>, and_so_on<Pasta>, and_so_forth<T,etc<T>>> { /* ... */ }; // example 2 class A : public particular = particular_t<my_allocator<double>> { /* ... */ }; // example 3 class A : public Bx = B<X>, public By = B<Y> { /* ... */ };
The proposed syntax is currently ill-formed and thus will not affect existing code.
The format is chosen for its similarity to the existing alias-declaration.
The following changes to the grammar are required:
A typedef-name can be introduced with a base-alias if the base-type-specifier is preceded by an identifier and an equals sign. The semantics are the same as if the name was defined with a typedef in the base class, except it is only introduced into the scope of the derived class and is only available after the base-alias is declared. The aliased name, therefore, has the same accessibility as the inherited base class name.
The standards and terms are taken from the working draft
N3797.
http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2013/n3797.pdf